35x^2-3x-20=0

Solution for 35x^2-3x-20=0 equation:

35x^2-3x-20=0

a = 35; b = -3; c = -20;
Δ = b2-4ac
Δ = -32-4·35·(-20)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-53}{2*35}=\frac{-50}{70}
=-5/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+53}{2*35}=\frac{56}{70}
=4/5
$